Work Done by Force in First 4 Secs: 0

[Bhumanyu Arun]

1. The position x of a particle moving along x-axis at time t is given by the eqn, t=(√x)+2.,where x is in m and t is in s. Find the work done by force in first 4 sec2. W=F.s=mas

I first found out x using the given eqn nd then went blank as there was no force or mass given. But the ans is 0

 

[gneill]

Please keep the formatting headers in place when you post a homework problem.

Can you supply the details about work you've done so far? (show your equations) There may be some answers to your stated issues hidden in plain sight

 

[cnh1995]

2. W=F.s=mas

Here s is 'displacement' of the particle i.e. "change" in the value of 'x' in the equation. Does that ring any bells?

 

[Bhumanyu Arun]

Here s is 'displacement' of the particle i.e. "change" in the value of 'x' in the equation. Does that ring any bells?

Great, got it. There ain't no displacement. Coz the initial as well as final position is 2. Thanx sir.

 

[Bhumanyu Arun]

Thnx for clearing my stuff everyone. Hope to get ur support always

 

[cnh1995]

Coz the initial as well as final position is 2.

Its 4 actually..But its great you got the concept!

Thanx sir.

I'm a student, probably of your age,20.

 

[Bhumanyu Arun]

That was such a silly mistake. Well I m 2 years younger.