(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

How much work is done by a force= (2x)i N + (3)j N with x in meters, that moves a particle from a position (initial) = (2m)i + (3m)j to a position (final) = (-4m)i + (-3m)j?

Answer:

- 6 J

2. Relevant equations

Work = integral of Force

3. The attempt at a solution

W = [x^2] i + [3x] j

W = [4^2 - 2^2] i + [3(-3) - 3(3)] j

W = 12 i -18 j

W magnitude = 21.6J

I realize I am doing this wrong becasue the Magnitude will always be positive and the answer (from back of book) is negative.

I tried this in a similar way where I took the difference between the two position vector and then placed it in the integral

rd = (-6) i + (-6) j

Got W = 36 i + 18 j

still wrong.

Help, pretty please?

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# Work done by force (Vector notation)

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