1. The problem statement, all variables and given/known data How much work is done by a force= (2x)i N + (3)j N with x in meters, that moves a particle from a position (initial) = (2m)i + (3m)j to a position (final) = (-4m)i + (-3m)j? Answer: - 6 J 2. Relevant equations Work = integral of Force 3. The attempt at a solution W = [x^2] i + [3x] j W = [4^2 - 2^2] i + [3(-3) - 3(3)] j W = 12 i -18 j W magnitude = 21.6J I realize I am doing this wrong becasue the Magnitude will always be positive and the answer (from back of book) is negative. I tried this in a similar way where I took the difference between the two position vector and then placed it in the integral rd = (-6) i + (-6) j Got W = 36 i + 18 j still wrong. Help, pretty please?