Work Done by Gravity: Formula & Considerations

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Homework Help Overview

The discussion revolves around the work done by gravity on a falling ball, specifically considering the effects of air resistance. The original poster presents a scenario involving a ball falling from a height of 20m, with given values for gravitational acceleration and mass, and questions the application of the work formula in the presence of air friction.

Discussion Character

  • Exploratory, Assumption checking, Conceptual clarification

Approaches and Questions Raised

  • Participants explore the formula for work done by gravity and whether it remains constant despite air resistance. Questions arise about the implications of air friction on the net work done and the validity of using W=F*s in this context.

Discussion Status

Participants are actively discussing the relationship between gravitational work and the work done by air resistance. Some clarify that while the work done by gravity remains the same, the total work is affected by air resistance, leading to a nuanced understanding of the situation.

Contextual Notes

There is an ongoing examination of the assumptions regarding constant gravitational force and the qualitative effects of air resistance on the work done. The original poster expresses uncertainty about the concepts of work and the impact of air friction, which is acknowledged by others in the discussion.

alingy1
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Let's say a ball falls from a height of 20m from the ground. g=9,8m/s^2. m=3kg.
Consider resistance of air in a qualitative way.

What's the formula for the work done by gravity?

So, I just thought about this question. I wonder if W=F*s should be applied. Does gravity still do 588J of work? Or should we take into account that F is smaller because of air friction? All this concept of work is very new to me and I googled for similar questions but couldn't find any web page alluding to my problem.
 
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If considering air resistance, then the net work is not the same as the work done by gravity, which is the same regardless of air resistance.

Your notion of W=F*S works if you treat gravity as an approximately constant force, but that approximation becomes poor as S gets larger. This all comes from the fact that the gravitational force on Earth or any other planet is actually given by Newton's Laws of Gravitation, which creates a more difficult work calculation.

You should also note that work is not simply F*S.

See: https://en.wikipedia.org/wiki/Work_(physics )
 
Last edited by a moderator:
alingy1 said:
Let's say a ball falls from a height of 20m from the ground. g=9,8m/s^2. m=3kg.
Consider resistance of air in a qualitative way.

What's the formula for the work done by gravity?

So, I just thought about this question. I wonder if W=F*s should be applied. Does gravity still do 588J of work? Or should we take into account that F is smaller because of air friction? All this concept of work is very new to me and I googled for similar questions but couldn't find any web page alluding to my problem.

The force due to gravity is the same, the distance fallen is the same, so the Work done by gravity should still be the same.
HOWEVER: the resistance of air will be doing some work too.
 
Okay, so, the total work done (not only by g) will be smaller than the work that should have been done without air. The air does negative work and g, the same work.
 
alingy1 said:
Okay, so, the total work done (not only by g) will be smaller than the work that should have been done without air. The air does negative work and g, the same work.

Correct. It is similar to pushing a box with friction opposing the push. You do work with your own force F_p as you move the block, while the ground also does work in the OTHER direction (different signs) with the frictional force F_f doing work as the block moves.
 

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