Work Done by Gravity on an Incline

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SUMMARY

The work done by gravity on an incline is accurately represented by the formula m*g*h, which can also be expressed as m*g*d*sinθ, where θ is the angle of the incline with the horizontal. The confusion regarding the formula m*g*d*cosθ is clarified, as it does not apply in this context. The discussion emphasizes the importance of understanding the geometric relationships in a right triangle formed by the incline, specifically using the sine function to determine the height. Additionally, the sign of the work done varies depending on the direction of travel along the incline.

PREREQUISITES
  • Understanding of basic physics concepts, particularly gravitational force.
  • Familiarity with trigonometric functions, specifically sine and cosine.
  • Knowledge of inclined planes and their geometric properties.
  • Ability to visualize and draw right triangles in physics problems.
NEXT STEPS
  • Study the derivation of work done by gravity on inclined planes.
  • Learn about the implications of positive and negative work in physics.
  • Explore the applications of trigonometric functions in physics problems.
  • Investigate different scenarios involving motion on inclined planes, including friction effects.
USEFUL FOR

Students of physics, educators teaching mechanics, and anyone interested in understanding the principles of work and energy on inclined surfaces.

johnhuntsman
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The formula is m*g*h which translates to m*g*d*sinθ right? I have it written down as m*g*d*cosθ on my formula chart for some reason which doesn't make sense, and I want to reassure myself.
 
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The formula is m*g*h which translates to m*g*d*sinθ right?
Yes, where theta is the angle the incline makes with the horizontal. Draw the right triangle with height h and hypotenuse d, and use soh-cah-toa...but what is the sign of the work done, if the object is traveling up the plane? Down the plane?
 
Okay then. Thanks.
 

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