Hi I think I figured it but I'm not sure.(adsbygoogle = window.adsbygoogle || []).push({});

Here's the problem:

How Much Work In Fig. 25-34, how much work is required to bring the charge of +5q in from infinity along the dashed line and place it as shown near the two fixed charges +4q and –2q? Take distance d = 1.40 cm and charge q = 1.6 × 10–19 C.

I summed up the Vpotential at the point which I got 0 Volts

Then I used W = qt(Vp-Vinfinity) = 0J. It just seems too simple to be correct.

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# Homework Help: Work Done by moving point charge

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