1.A 2.0 kg mass is spun in a horizontal circle at the end of a 0.66 m long string at a speed of 12 m/s. What is the work done by tension when the mass has gone halfway around the circle? A) 576 J B) 1810 J C) 904 J D) 0 2. Relevant equations Fc=mv^2/r and w=f*d 3. The attempt at a solution Well I first calculated the centripital force using the first equation. (2kg)(12m/s^2)/.66 and got 4.36N. The I used work=f*d and got 8.17. This is not even an answer. Any sugestions?