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## Homework Statement

An adiabatic process is performed on 15 moles of an ideal gas. The initial temperature is 320 K and the initial volume is

0.80 m3. The final volume is 0.40 m3. The adiabatic constant for the gas is 1.44. How much work is done by the gas?

The answer is -32kJ

## Homework Equations

W = Integrate[p dv, vInitial, vFinal] for adiabatic processes

pV = nRT

## The Attempt at a Solution

If p(v^y) initial == p(v^y) final where y = 1.44, and v varies, then p also varies, and I don't know how to use a varying pressure with the formula for work for adiabatic processes.

I try to find the initial pressure by

pV = nRT

p*V == 15*8.31*320

With Vinitial, p = 49860Pa

With Vfinal, p = 99720Pa

And I'm stuck.