Work done on object vs work done by you

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The discussion clarifies the distinction between work done on an object and work done by an individual. Work done on the mass involves all forces acting on it, including friction, and corresponds to the change in kinetic energy. In contrast, work done by the individual is calculated as the force exerted multiplied by the displacement of the mass. The conversation emphasizes that not all energy expended by the individual contributes to the work done on the mass, as some energy is lost to heat and other forms. Understanding these differences is crucial for solving related physics problems effectively.
rusty711
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What is the difference between work done on an object and work done by you?

For example, you exert a 100N force pushing a 10kg mass 3.0m across the floor with a coefficient of friction 0.60
1) what is the work done on the mass?
2) what is the work done by you?

For question 1 I think it has to do with a change in kinetic energy, and 2 with kinetic energy and heat energy, but I'm not sure how to solve? Thanks!
 
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Work done by you is manifest as sweat.
 
But how do I solve these? What's the difference
 
You should be able to see the difference by doing the calculation. Start from the equation for work.
What is the total force on the mass? How far does it move?
What is the total force on "you"? How far do "you" move?

Basically: Things doing work lose energy.
I think what they want you to notice is that not all the work done by "you" is done on the mass.
Where else could your energy be going?
 
rusty711 said:
What is the difference between work done on an object and work done by you?

For example, you exert a 100N force pushing a 10kg mass 3.0m across the floor with a coefficient of friction 0.60
1) what is the work done on the mass?
2) what is the work done by you?

For question 1 I think it has to do with a change in kinetic energy, and 2 with kinetic energy and heat energy, but I'm not sure how to solve? Thanks!

The work done on the mass includes the work of all the forces, both yours and the force of friction (the work of the resultant force) which is equal to the change of kinetic energy.
Recall: work is force times displacement. Your work is equal to your force times the displacement of the mass.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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