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Work done to pull the entire chain

  1. Mar 1, 2013 #1
    1. The problem statement, all variables and given/known data
    A chain of mass 4Kg and length 2m is lying on a table, such that 60 cm of one end is hanging from one edge off the table. Find the work done to pull the entire chain on the table.

    2. Relevant equations
    (anything that'll work i suppose)

    3. The attempt at a solution
    I thought that the work done to do this is simply the work done against gravity to lift the hanging mass.
    The mass per unit length of the chain is λ=m/l=2Kg/m
    So the mass of the hanging portion is λ*60cm=2*0.6Kg=1.2Kg
    So the work done to lift it 0.6m up is 1.2*9.8*0.6J=7.056J

    But the given answer is 3.6J.
    What am I doing wrong?
     
  2. jcsd
  3. Mar 1, 2013 #2
    You assumed that the entire mass of the portion of the chain that needs to be lifted is 0.6 m below that table. But that is not correct. Most of the portion is above that. And those parts need less work. How could you take this into account?
     
  4. Mar 1, 2013 #3
    I don't get that! The mass that's on the table is on the table! So shouldn't I lift only the part that's hanging?
     
  5. Mar 1, 2013 #4
    The part that is hanging is contiguous. Only its end is 0.6 m below the table. The other bits of the hanging part are still below the table, but HIGHER than 0.6 m.
     
  6. Mar 1, 2013 #5
    Oh yeah!!! of course!! so if I assume lifting the centre of mass of the hanging portions, then I lift 1.2Kg by 0.3m!!! the answer then comes!! thanks.
     
  7. Mar 1, 2013 #6
    Correct.
     
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