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## Homework Statement

A ##10.0kg## block falls ##30.0m## onto a vertical spring whose lower end is fixed to a platform.When the spring reaches its maximum comprassion of ##0.200m##,it is locked in place.The block is then removed and spring apparatus is transported to the Moon,where the gravitational acceleration is ##\frac g 6##.

A ##50.0kg## astronaut then sits on top of the spring and the spring is unlocked so that it propels the astronaut upward.How high above the initial point does the astronaut rise ?

## Homework Equations

[/B] ##Δ(ME)=0##

## U_s=\frac 1 2kx^2##

## The Attempt at a Solution

##\frac 1 2kx^2-mg(30.2)=0##

then we take the system to the moon.

Let's write another ##Δ(ME)=0##

## mgh-\frac 1 2kx^2=0## In the highest point the kinetic energy will be zero.So the change in kinetic energy is zero.

In both equations ##\frac 1 2kx^2## are same and If we put new mass and new ##g## we get same answer which its ##30.2m## but answer says its ##36m##.

Probably I forget some energy term somewhere or I took wrong height Idk

Thanks