Work help i'm stuck and about to kill myself

In summary, the tangential acceleration of the car is 0.83 m/s^2 (tangent to the path) and the radial acceleration is 3.7 m/s^2 (toward the center of the path). To provide this acceleration without slipping or skidding, the coefficient of static friction between the tires and the roadbed would have to be 0.48. The key to solving this problem is understanding the relationship between tangential and radial acceleration and utilizing the equations provided in the given resources.
  • #1
howru
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work help! I'm stuck and about to kill myself

A car at the Indianapolis-500 accelerates uniformly from the pit area, going from rest to 320 km/h in a semicircular arc with a radius of 192 m.

Determine the tangential acceleration of the car when it is halfway through the turn, assuming constant acceleration.
m/s^2(tangent to the path)
(I know that the equation is equal to mv2/r but how do i set it up. what is the difference between tangent and toward the center.)

Determine the radial acceleration at this time.
m/s^2 (toward the center of the path)
(It is rev/sec and multiply. i got 3.7m/s^2)

If the curve were flat, what would the coefficient of static friction have to be between the tires and the roadbed to provide this acceleration with no slipping or skidding?

(mu=fN I got all these other formulas and forces on the car and put them together, and i got .48 but it's wrong)
 
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  • #2
This might help.
http://hyperphysics.phy-astr.gsu.edu/hbase/rotq.html, specifically http://hyperphysics.phy-astr.gsu.edu/hbase/rotq.html#req

and this is a nice reference

http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html#rlin

The tangential velocity is the linear velocity tangent (parallel) to the trajectory, which is perpendicular to the radial direction for a semi-circle.

The key here is that the acceleration is uniform. The car starts with 0 velocity and reaches 320 km/h at the end of the semi-circle of radius 192 m, and it must travel a distance x = [itex]\pi[/itex]*192 m. Note that the angle through which the acceleration takes place is [itex]\pi[/itex] radians.
 
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