Work input to a pump in a rankine cycle problem

Click For Summary
SUMMARY

The discussion centers on the interpretation of work input to a pump in a Rankine cycle problem. The participant argues that presenting the work input as a positive quantity is acceptable since the direction of energy transfer is defined in the question. However, they acknowledge that conventional thermodynamic principles dictate that work done on a system, such as the work input to a pump, is negative. The disagreement with the lecturer highlights the importance of adhering to established sign conventions in thermodynamics.

PREREQUISITES
  • Understanding of Rankine cycle principles
  • Familiarity with thermodynamic sign conventions
  • Knowledge of steady state steady flow equations
  • Basic concepts of work and energy transfer in thermodynamics
NEXT STEPS
  • Review thermodynamic sign conventions in detail
  • Study the application of the steady state steady flow equation to pumps
  • Explore the differences between work input and work output in thermodynamic systems
  • Investigate common misconceptions in thermodynamics education
USEFUL FOR

Students of thermodynamics, educators teaching thermodynamic principles, and engineers working with Rankine cycle systems will benefit from this discussion.

jemb
Messages
11
Reaction score
0
If a question asks for the "quantity of work input to the pump" is it acceptable to present the answer as positive.

I think so because the direction of energy transfer has been defined in the question itself hence there is no need for a sign on the answer. All that's asked for is the quantity. However my thermodynamics lecturer disagrees and is refusing to award the marks for the answer in a recent coursework submission.

I understand why work input in thermodynamics is negative, but surely an unsigned figure is permissible if the direction of energy transfer is defined for you.

Am i wrong?
 
Physics news on Phys.org
Usually the sign convection for work done is that work done by something is positive while work into a system is negative.

Since you are inputting work to a system, then the work done by the pump is negative.

This is why the turbine does positive work.

(Apply the steady state steady flow equation to the pump and you will see)
 

Similar threads

  • · Replies 8 ·
Replies
8
Views
6K
  • · Replies 1 ·
Replies
1
Views
4K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
18
Views
5K
  • · Replies 1 ·
Replies
1
Views
4K
Replies
23
Views
5K
  • · Replies 6 ·
Replies
6
Views
6K
Replies
1
Views
3K
  • · Replies 2 ·
Replies
2
Views
2K