Work/Kinetic energy, running a race with mass and speed

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SUMMARY

The discussion centers on a physics problem involving kinetic energy and mass in a racing scenario. The participant has a mass of 81 kg and increases their speed by 21% to match their friend's speed. The kinetic energy equation, KE = 1/2 mv², is utilized to derive the relationship between the two racers' masses and speeds. The solution requires setting up two equations to account for the different speeds while maintaining equal kinetic energy.

PREREQUISITES
  • Understanding of kinetic energy and its formula (KE = 1/2 mv²)
  • Basic algebra for solving equations
  • Concept of percentage increase in speed
  • Ability to differentiate between variables in equations
NEXT STEPS
  • Study the derivation of kinetic energy equations in physics
  • Learn how to solve simultaneous equations
  • Explore the concept of mass and acceleration in relation to speed
  • Investigate real-world applications of kinetic energy in sports
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Students studying physics, educators teaching mechanics, and anyone interested in understanding the principles of kinetic energy and motion in competitive scenarios.

Willy_Kingston
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Homework Statement


You run a race with your friend. At first you each have the same kinetic energy, but then you find that she is beating you. When you increase your speed by 21%, you are running at the same speed she is. If your mass is 81 kg, what is her mass?
Your mass: 81kg
Your speed is increased by 21%
Her speed:?

Homework Equations


KE=1/2mv2



The Attempt at a Solution


1/2mv2=1/2mv2
1/2(81)v2=1/2?v2
 
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Willy_Kingston said:
1/2mv2=1/2mv2
That's not a terribly useful equation. Try using different symbols for different variables, e.g. the two masses and the two speeds. If you find subscripting a pain, combine upper and lower case, like Ma, Mb.
 
Willy_Kingston said:
1/2mv2=1/2mv2
1/2(81)v2=1/2?v2


Apart from the fact that you should give different names, you are considering both kinetic energy and speed equal at the same time... but it is not what the problem asks you...

When kinetic energy is the same, speeds are different; speeds are equal after you increasing speed. You will need two equations for solving this
Hint: write in equations the two different informations I gave you... it will solve by itself then :smile:
 

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