Work needed to stretch a spring

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SUMMARY

The work needed to stretch a spring with a spring constant of k = 88 N/m from an initial displacement of x = 4.2 cm to a final displacement of x = 6.2 cm can be calculated using the area under the force versus displacement graph. The force exerted by the spring is given by Fs = kx, which results in a force of 176 J for a displacement of 2 cm. This calculation confirms that the work done is directly related to the change in displacement and the spring constant.

PREREQUISITES
  • Understanding of Hooke's Law (Fs = kx)
  • Basic knowledge of graph interpretation
  • Familiarity with work-energy principles
  • Ability to calculate areas under curves
NEXT STEPS
  • Learn how to calculate work from a force/distance graph
  • Study the concept of potential energy in springs
  • Explore advanced applications of Hooke's Law
  • Investigate the relationship between spring constants and material properties
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and energy, as well as educators seeking to explain the principles of spring dynamics and work calculations.

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Homework Statement



A spring has k = 88 N/m. Use a graph to determine the work needed to stretch it from x = 4.2 cm to x = 6.2 cm, where x is the displacement from its unstretched length.

Homework Equations



Fs=kx

The Attempt at a Solution



Fs=-kx
=(88)(2)
Fs=176 J
 
Last edited:
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The question asks you to determine the work done from a graph. Do you know how to calculate work from a force/distance graph?
 

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