1. The problem statement, all variables and given/known data A 1 kg particle starts from rest at x = 0 and moves under the influence of a single force Fx = 6.6 + 12.6x - 1.8x2, where Fx is in Newtons and x is in meters. Find the work done by this force on the particle as the particle moves from x = 0 m to x = 1.5 m. Find the power delivered to the particle when it is at x = 1.5 m. 2. Relevant equations Integrals V = (2K/m)1/2 P = Fv 3. The attempt at a solution I solved the first part by solving the integral and plugging in 1.5. The answer was 22.05. The second part I thought I had correct: V = (2K/m)1/2, where K = W V = (2(22.05)/1.5)1/2 V = 119.56 W I tried variations on this number because I was certain I was correct, I even tried the negatives. Perhaps my equation for V is incorrect?