- #1

iJamJL

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## Homework Statement

A highway goes up a hill, rising at a constant rate of 1.00 m for every 48 m along the road. A truck climbs this hill at constant speed vup = 19 m/s, against a resisting force (friction) f equal to 1/24 of the weight of the truck. Now the truck comes down the same hill, using the same power as it did going up. Find vdown, the constant speed with which the truck comes down the hill.

ASSUME: the resisting force (friction) has the same magnitude going up as going down.

## Homework Equations

W=F*s

F=μ*N

## The Attempt at a Solution

Not really sure how to start this problem. What I've done so far is I've drawn this picture out, and that's all I can do. I drew it on a graph, and so the slope is 1/48 because the truck goes up 1 meter for every 48 meters it moves to the right of the origin. Then, the frictional force is applied downhill when the truck is traveling up, and the opposite when the truck is traveling down. I'm trying to find the power, or at least work, of the truck traveling up the hill, but it's not very clear because it doesn't say how far it traveled. We could use the measure of traveling to right 48m and 1m up, and then use that same amount to travel back down, but I'm still having trouble beginning this problem.