Work Problem: Climbing 3000m Mountain with 50kg Woman

[genPhysics]

Homework Statement

A 50kg woman climbs a 3000m mountain high. a) how much work does she do against the gravitational forces? b) a kilogram of fat supplies 3.8 x 10^7 J of energy. If she converts fat into mechanical energy with a 20% efficiency rate, how much fat will she consume in the climb?

Homework Equations

E= Einitial + Wa or K + U = Kinitial + Uinitial + Wa

K= 1/2mv^2 and U=mgh

thanks.. I really appreciate it.

 

[rl.bhat]

Work done against the gravitational force is stored as the potential energy. From the relevant equation given by you can find this energy.
Find 20% of that energy. From that find the fat consumption.