Work Problem: Climbing 3000m Mountain with 50kg Woman

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SUMMARY

The discussion focuses on calculating the work done by a 50kg woman climbing a 3000m mountain and the subsequent fat consumption based on energy conversion. The work against gravitational forces is determined using the potential energy formula U = mgh, resulting in 147,000 Joules. Given that a kilogram of fat supplies 3.8 x 10^7 J of energy and the conversion efficiency is 20%, the woman will consume approximately 0.02 kg of fat during the climb.

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  • Understanding of gravitational potential energy (U = mgh)
  • Familiarity with energy conversion efficiency concepts
  • Basic knowledge of work-energy principles
  • Ability to perform unit conversions and calculations
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Homework Statement



A 50kg woman climbs a 3000m mountain high. a) how much work does she do against the gravitational forces? b) a kilogram of fat supplies 3.8 x 10^7 J of energy. If she converts fat into mechanical energy with a 20% efficiency rate, how much fat will she consume in the climb?

Homework Equations



E= Einitial + Wa or K + U = Kinitial + Uinitial + Wa

K= 1/2mv^2 and U=mgh

thanks.. I really appreciate it.
 
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Work done against the gravitational force is stored as the potential energy. From the relevant equation given by you can find this energy.
Find 20% of that energy. From that find the fat consumption.
 

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