Working out the frequency/wavelength of a photon.

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SUMMARY

The discussion focuses on calculating the frequency and wavelength of a photon emitted when an electron transitions from the 4th energy level to the 3rd energy level in an atom. Using the energy difference of -0.33 x 10-18 J, the frequency is calculated using the equation E=hf, resulting in a frequency of 4.977 x 1014 Hz. The wavelength is then derived using the speed of light, yielding a value of 6.0277 x 1021 m, which is incorrect due to a calculation error in the frequency. The correct frequency should be expressed as 4.977 x 1014 Hz.

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  • Understanding of quantum mechanics principles, specifically energy levels in atoms.
  • Familiarity with the Planck-Einstein relation (E=hf).
  • Knowledge of the speed of light (c) and its significance in wave calculations.
  • Basic algebra skills for manipulating equations and performing calculations.
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Homework Statement



In an atom, an electron goes from the 4th energy level (at -0.26J x 10-18) to the 3rd energy level (at -0.59J x 10-18) and a photon is subsequently released.

How do you work out the frequency of the photo and its wavelength.

Homework Equations



E=hf
wavelength = c/f

The Attempt at a Solution



E=hf

Therefore, f=E/h so...

-0.59 - -0.26 = -0.33

so...

f = 0.33 x 10-18 / 6.63 x 10 -34

= 4.977 x10-14 Hz

And as wavelength = c/f...

wavelength = 3x108 (Speed of light) / 4.997 x10-14 = 6.0277 x1021

However, the wavelength surely can't be that large?! Where did I make a mistake?
 
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physics369 said:
f = 0.33 x 10-18 / 6.63 x 10 -34

= 4.977 x10-14 Hz

And as wavelength = c/f...

wavelength = 3x108 (Speed of light) / 4.997 x10-14 = 6.0277 x1021
this f should f = 4.977(10+14) Hz.
 

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