What is the Photon Flux for a 100 MHz Signal Traveling 4 Light Years Away?

Click For Summary

Homework Help Overview

The discussion revolves around calculating the photon flux for a signal with a frequency of 100 MHz that is traveling a distance of 4 light years. The original poster attempts to understand how to relate frequency, energy, and power to find the number of photons and the necessary size of a detector.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between photon energy, power, and the number of photons. Questions are raised about the appropriate equations to use and how to calculate the number of photons arriving per second and per frame.

Discussion Status

Some participants provide guidance on how to calculate the number of photons using power and photon energy. There is an exploration of how to account for the number of frames per second in the calculations. Multiple interpretations of the problem are being discussed, particularly regarding the fraction of photons needed for detection.

Contextual Notes

Participants note the constraints of the problem, including the distance of 4 light years and the power of the signal being considered. There is an emphasis on understanding the underlying physics without seeking direct answers.

Ashley1nOnly
Messages
132
Reaction score
3

Homework Statement


It's in attachment

Homework Equations



E=hf. Where h= planks constant and f= frequency

The Attempt at a Solution


I know that the flux of a photon is (# of photons)/(sec m^2)
I don't know the number of photos but I do know the frequency and power.

E=(6.6261*10^(-34)) J•s * (100 MHz)=6.621*10^-32
Also
Wavelength*frequnecy=c
I know that it's traveling 4 light years away.

Wavelength*(100MHz)=4c
Wavelength=4c/(100MHz

What equation am I supposed to use and how do I find the number of photon and how big in diameter would the recover/detector have to be. I don't want the answer just help understanding the problem and what I'm doing wrong. Or am I on the right track

Thanks in advance
 

Attachments

  • image.jpeg
    image.jpeg
    87.9 KB · Views: 479
Last edited:
Physics news on Phys.org
The image has a wrong orientation.

You know the energy per photon, and the power. Can you get the photons per second, or per image frame?
To capture all photons in a distance of 4 light years, aliens would have to construct a sphere with a radius of 4 light years. They don't need all the photons, of course, but which fraction do they need?
 
I know the
energy is 6.621*10^-32
power is 100Kw 24 frames per second.

what equation should i use to relate them
 
I can do the power divided by the photon energy to get the number of photons arriving per second100 KW/ 6.21*10^-32
 
Ashley1nOnly said:
I can do the power divided by the photon energy to get the number of photons arriving per second
Right.
As every second has 24 frames, how many photons are there per frame?

All those steps all don't need fancy physics.
 
power divided by / ( the photon energy * 24) to get the number of photons per frame
 

Similar threads

Replies
15
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 6 ·
Replies
6
Views
5K
  • · Replies 11 ·
Replies
11
Views
21K
  • · Replies 3 ·
Replies
3
Views
3K
Replies
4
Views
2K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 6 ·
Replies
6
Views
8K