Working out the geostationary orbit

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Homework Help Overview

The discussion revolves around calculating the geostationary orbit of a moon around a fictional planet with a specified diameter and density. The original poster seeks assistance in determining the mass of the planet to find the radius of the geostationary orbit.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • The original poster attempts to use the formula for the radius of the geostationary orbit but is unsure how to calculate the mass of the planet from its volume and density. Other participants suggest calculating the volume based on the planet's diameter and using the provided density to find the mass.

Discussion Status

The discussion is ongoing, with participants exploring the necessary calculations and clarifying the units involved. There is a recognition of the need to derive the mass from the planet's volume and density, but no consensus has been reached on the approach.

Contextual Notes

There is a correction regarding the density unit from cubic metres to kilograms per cubic metre, which is crucial for the calculations. Additionally, the thread has been noted as a homework help forum, indicating a focus on educational assistance rather than contest solutions.

dread
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I have been given that this planet has a diameter of 1600km with a uniform density of 52000 per cubic metre. And if its moon is in a geostationary orbit around the planet and assuming that the sidereal is exactly 24 hours. How far is the geostationary orbit above the surface of the planet. And i need the answer in km.

I'm stuck in getting the mass of the planet as so far i have

radius of the geostationary orbit = cubed root of (GMpT2p over 4 pi 2)

so therefore the radius = cubed root of (6.6742 x 10-11 x (mass of the planet which i do not know how to find out x 864002 all over 4 pi 2)

some help would be much appreciated

thanks
 
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I guess you would have to calculate the volume of the planet?
I guess you would then do something with the density (for which you lack a unit)?
Somehow, magically, this leads to the mass of the planet?
 
thanks well I've posted it there now and yeah sorry it was meant to be 5200kg per cubic metre I've changed it for the new post now
 
Neopets "Lenny Conundrum" contest, Round 271 (closes 23 July)

dread said:
I have been given that this planet has a diameter of 1600km with a uniform density of 52000 per cubic metre...

The actual text of this week's Neopets "Lenny Conundrum" contest puzzle (Round 271) is as follows:

"Assume the world of Neopia is a spherical planet with a diameter of 1600 km with a uniform density of 5200 kilograms per cubic metre. If the moon of Kreludor is in a geostationary orbit around Neopia, and assuming a Neopian sidereal day is exactly 24 hours, how far is that geostationary orbit above the surface of Neopia?"

To get the prize-winning answer for the latest "Lenny Conundrum" contest, try following the instructions here:

. . . . .[/color]Lenny Conundrum Solutions Blog

Another resource might be http://www.able2know.org/forums/viewtopic.php?t=42093 .

Eliz.
 
Last edited by a moderator:
This is a homework help forum, designed to help students with their homework/classwork problems, not to answer quiz, or contest problems. Thus, I am closing this thread now.
 

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