Working out the speed a parked car travels after a moving car hits it

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SUMMARY

The discussion focuses on calculating the speed of a parked car (Car A) after being hit by a moving car (Car B) using the principles of momentum conservation. Car A has a mass of 1840 kg and is initially at rest, while Car B has a mass of 1400 kg and an initial speed of 26.82 m/s. After the collision, Car B continues at a speed of 8.4 m/s, resulting in a transferred momentum of 25788 kg·m/s to Car A. The correct approach involves using the conservation of momentum formula, p = mv, to determine Car A's final speed.

PREREQUISITES
  • Understanding of momentum conservation principles
  • Familiarity with Newton's second law of motion (F=ma)
  • Basic knowledge of mass and velocity calculations
  • Ability to apply algebraic manipulation to physics equations
NEXT STEPS
  • Study the conservation of momentum in elastic and inelastic collisions
  • Learn how to calculate final velocities after collisions using momentum equations
  • Explore real-world applications of momentum in vehicle crash analysis
  • Investigate the effects of mass and speed on collision outcomes
USEFUL FOR

This discussion is beneficial for forensics students, physics students, and professionals involved in accident reconstruction or vehicle safety analysis.

reefcake
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Hi I'm forensics student and I'm having trouble with this problem as i don't know how to solve it I would really like to to know the method.

Homework Statement


Calculate the speed in ms-1 at which a parked 1840kg "car A" will be traveling once "car B" crashes into it. assuming that "car B" continues to move forward at 8.4ms-1 after the crash.

info on Car A: Mass(m)= 1840kg, Speed(v)=0 ms-1

info on Car B: Mass(m)= 1400kg, Speed(v)= 26.82 ms-1 Momentum(p), 37548 kg-ms-1
ending speed= 8.4ms-1, Ending momentum= 11760 kg-ms-1

Homework Equations


p=mv (conservation momentum)
F=ma (Newtons 2nd law of motion)
A= uv/t (working out acceleration)



Thanks

reefcake
 
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Welcome to PH.

After the collision, what momentum will Car A have if momentum is really conserved?
 
SammyS said:
Welcome to PH.

After the collision, what momentum will Car A have if momentum is really conserved?

Hi again ;)

yes that is problem as I'm not sure to go about working out as Car B transfers (p)25788kg-ms to car a but Car A is 1840kg, 440 kg heavier. do i divide (p)25788kg-ms (which is the transferred momentum) by 1840kg to get the speed of CarA?

thanks
 
Last edited:

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