1. The problem statement, all variables and given/known data A) A car of mass 1000 kg is acted on by a net force of 2500 N. What is the resulting acceleration? B) A car of mass 1000 kg pulls a caravan of mass 800 kg; the driving wheels of the car exert a force of 8000 N on the road. The total resistance to motion is 3000 N. B1) What is the net accelerating force? B2) What is the acceleration? B3) What is the force of the car on the caravan? C) An engine of mass 5000 kg pulls a train of ten trucks each of mass 2000 kg along a horizontal track. Assume that the frictional forces to be 5000 N and that the engine exterts a force of 50,000 N on the rails. If the trucks are numbered from 1 to 10 starting with the one next to the engine calculate: C1) The net total acceleration force C2) The acceleration of the train C3) The force of truck 6 on truck 7 C4) The force of truck 9 on truck 8 D) A rescue helicopter lifts a strecther case off a hillside. The injured climber and stretcher have a mass of 180 kg and the rope supporting them has a breaking force of 2000 N. Calculate: D1) The tension in the rope when the stretcher and climber are suspended from the rope at rest D2) The maximum vertical acceleration possible before the rope breaks 2. Relevant equations All I know and all that we have learned so far equation-wise is that F= ma and the pendulum equation. 3. The attempt at a solution A) F = ma 2500 N = 1000 kg * a 2500/1000 = 1000a/1000 2.5 m/s^2 = A B) m1 = 1000 kg m2 = 800 kg F = 8000 N resistance to motion = 3000 N B1) F= 5000N B2) F = ma 5000 = 1800 * a 2.78 m/s^2 B3) F = 800 (2.78) F = 2224 N C) I am pretty sure this is all wrong, but here's my attempt. Engine = 5000 kg Trucks = 2000 kg ( * 10) frictional F = 5000 N engine F = 50,000 N C1)F = 45,000 N C2) F = ma 45,000 = 20,000 * a a = 2.25 m/s^2 C3) C4) D) m = 180 kg F = 2000 N D1) F = ma F= 180 (9.8) F = 1764 N D2) F = ma 2000 = 180 *a 11.11 m/s^2 = a Thanks in advance!