Would sodium salicytate dissolve in any of them

[Alexestalex]

Homework Statement

Would sodium salicytate dissolve in any of the following solvents?

Water
Diethyl Ether
6% HCL
6% sodium bicarbonate
6% Sodium Hydroxide (naoh)

You don't have to but please explain your guess too. Thanks a lot.

Homework Equations

The Attempt at a Solution

I think it would dissolve in water due to the three Carbon Oxygen bonds it has (giving it a tad bit of polarity) but ever so slightly. The big cyclohexane is non polar which is why it wouldn't dissolve well.

I think it would dissolve well in diethyl ether, they are both extremely non polar. Diethyl ether is non polar due to its symmetry.

I think it would dissolve in HCL. HCL is electron poor while the O in sodium salicytate is electron rich. The electron rich O would grab the H and give the pair of electrons to CL.

The rest makes no sense to me.

 

[Borek]

What is - chemically - sodium salicylate?

(I assume you mean salicylate, I have no idea what salicytate is).

 

[Alexestalex]

Yes, that's what i meant.

 

[Borek]

So what it is?

 

[DeeNos]

I can confirm that your predictions are mostly correct. Sodium salicytate is a polar molecule due to the presence of the three carbon-oxygen bonds, which makes it more likely to dissolve in polar solvents such as water. However, the solubility will also depend on the concentration of sodium salicytate and the temperature of the solvent.

Diethyl ether is indeed a non-polar solvent and would likely dissolve sodium salicytate well due to similar intermolecular forces. HCl is a polar solvent and would also dissolve sodium salicytate due to the formation of hydrogen bonds between the hydrogen in HCl and the oxygen in sodium salicytate.

Sodium bicarbonate and sodium hydroxide are both basic solutions, and as you correctly pointed out, the electron rich oxygen in sodium salicytate would react with the electron poor hydrogen in these solutions, leading to dissolution.

Overall, it is important to note that the solubility of a compound depends on various factors, including the nature of the compound and the solvent, temperature, and concentration. Therefore, it is always best to conduct experiments to determine the solubility of a compound in different solvents.