Write 2nd order ODE as system of two 1st order ODEs

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SUMMARY

The discussion focuses on converting the second-order ordinary differential equation (ODE) given by d²y/dt² + 5(dy/dt)² - 6y + e^{sin(t)} = 0 into a system of two first-order ODEs. The correct transformation involves defining w = dy/dt, leading to the system: dy/dt = w and dw/dt = -5w² + 6y - e^{sin(t)}. Participants confirm that the solution provided in the book is incorrect, as it suggests an alternative formulation that does not align with the established mathematical principles.

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  • Understanding of ordinary differential equations (ODEs)
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  • Knowledge of transformation techniques in differential equations
  • Basic calculus, particularly differentiation
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s3a
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Homework Statement


Write the following second-order ODE as a system of two first-order ODEs.

##d^2y/dt^2 + 5(dy/dt)^2 - 6y + e^{sin(t)} = 0##

Homework Equations


w = dy/dt

The Attempt at a Solution


The solution of the book says ##dy/dt = w, dw/dt = -5w - 6y + e^{sin(t)}##, but shouldn't it be ##w = dy/dt, dw/dt = -5w^2 + 6y - e^{sin(t)}##, or am I missing something?
 
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I think you are missing the correct solution manual because I came to the same answer that you did ¯\_(ツ)_/¯
 
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Likes   Reactions: s3a
Lol, great. :P

Thanks!
 

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