Write an equation for the reaction of Al2O3 with hydroxide ions.

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SUMMARY

The reaction of aluminum oxide (Al2O3) with hydroxide ions (OH-1) can be represented by two equations. The first equation is Al2O3 + 2NaOH + 7H2O = 2Na[Al(OH)4(H2O)2], which indicates the formation of a complex ion in an aqueous solution. The second equation is Al2O3 + 2NaOH = 2NaAlO2 + H2O, which shows the formation of sodium aluminate. Both equations highlight the role of sodium (Na) as a spectator ion in the reaction.

PREREQUISITES
  • Understanding of chemical reactions and stoichiometry
  • Familiarity with hydroxide ions and their properties
  • Knowledge of aluminum oxide (Al2O3) and its chemical behavior
  • Basic principles of aqueous solutions and complex ion formation
NEXT STEPS
  • Research the properties and applications of sodium aluminate (NaAlO2)
  • Study the formation and significance of complex ions in aqueous chemistry
  • Explore the role of spectator ions in chemical reactions
  • Investigate the solubility and reactivity of aluminum compounds in alkaline solutions
USEFUL FOR

Chemistry students, educators, and professionals involved in inorganic chemistry and materials science will benefit from this discussion, particularly those focusing on aluminum compounds and their reactions in alkaline environments.

tieu
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write an equation for the reaction of Al2O3 with hydroxide ions.

Al2O3 + OH^-1 ----> ?
 
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tieu said:
write an equation for the reaction of Al2O3 with hydroxide ions.

Al2O3 + OH^-1 ----> ?
Al2O3+2NaOH+7H2O=2Na[Al(OH)4(H2O)2]
or melting together
Al2O3+2NaOH=2NaAlO2+H2O
 
geo_alchemist said:
Al2O3+2NaOH+7H2O=2Na[Al(OH)4(H2O)2]
or melting together
Al2O3+2NaOH=2NaAlO2+H2O

ummm Na is spectator ion rite?? are u allowed to put that in??
 
[Al(OH)4(H2O)2]^-1
AlO2^-1
 

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