Write an equation for the reaction of Al2O3 with hydroxide ions.

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Discussion Overview

The discussion revolves around writing an equation for the reaction of aluminum oxide (Al2O3) with hydroxide ions (OH^-). Participants explore different chemical equations and the roles of various ions in the reactions.

Discussion Character

  • Technical explanation
  • Debate/contested

Main Points Raised

  • Some participants propose the reaction Al2O3 + 2NaOH + 7H2O = 2Na[Al(OH)4(H2O)2] as a possible equation.
  • Others suggest an alternative reaction: Al2O3 + 2NaOH = 2NaAlO2 + H2O.
  • A participant questions whether sodium (Na) can be considered a spectator ion in these reactions and whether it is appropriate to include it in the equations.
  • Another participant provides the formulas [Al(OH)4(H2O)2]^-1 and AlO2^-1, possibly indicating different species involved in the reactions.

Areas of Agreement / Disagreement

Participants present multiple competing views regarding the correct equations for the reaction, and the discussion remains unresolved regarding the inclusion of sodium as a spectator ion.

Contextual Notes

There are limitations regarding the assumptions about the role of sodium ions and the specific conditions under which the reactions occur, which are not fully addressed in the discussion.

tieu
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write an equation for the reaction of Al2O3 with hydroxide ions.

Al2O3 + OH^-1 ----> ?
 
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tieu said:
write an equation for the reaction of Al2O3 with hydroxide ions.

Al2O3 + OH^-1 ----> ?
Al2O3+2NaOH+7H2O=2Na[Al(OH)4(H2O)2]
or melting together
Al2O3+2NaOH=2NaAlO2+H2O
 
geo_alchemist said:
Al2O3+2NaOH+7H2O=2Na[Al(OH)4(H2O)2]
or melting together
Al2O3+2NaOH=2NaAlO2+H2O

ummm Na is spectator ion rite?? are u allowed to put that in??
 
[Al(OH)4(H2O)2]^-1
AlO2^-1
 

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