MHB Write Ode as a System: Solving for $\theta$

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Can this be written as a system since it only has theta?
$$
U' = -\frac{mgb}{\sin^2\theta} - \frac{Mgb\cos\theta}{\sin^2\theta} = \frac{gb}{\sin^2\theta}(m - M\cos\theta).
$$
 
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Re: write ode has a system

dwsmith said:
Can this be written as a system since it only has theta?
$$
U' = -\frac{mgb}{\sin^2\theta} - \frac{Mgb\cos\theta}{\sin^2\theta} = \frac{gb}{\sin^2\theta}(m - M\cos\theta).
$$

I am trying to find the fixed points of this system. That is why I wanted to transform it. Can they be found in its current state?
 
I have the equation ##F^x=m\frac {d}{dt}(\gamma v^x)##, where ##\gamma## is the Lorentz factor, and ##x## is a superscript, not an exponent. In my textbook the solution is given as ##\frac {F^x}{m}t=\frac {v^x}{\sqrt {1-v^{x^2}/c^2}}##. What bothers me is, when I separate the variables I get ##\frac {F^x}{m}dt=d(\gamma v^x)##. Can I simply consider ##d(\gamma v^x)## the variable of integration without any further considerations? Can I simply make the substitution ##\gamma v^x = u## and then...

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