Writing the Full Equation of Acidified KMnO4 & KI

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Discussion Overview

The discussion revolves around the full equation for the reaction between acidified potassium permanganate (KMnO4) and potassium iodide (KI). Participants explore the ionic equation provided and seek clarification on how to express the full molecular equation.

Discussion Character

  • Technical explanation, Debate/contested

Main Points Raised

  • One participant presents an ionic equation for the reaction: 2 MnO4- + 16 H+ + 10I- --> 2Mn2+ + 8H2O + 5I2-.
  • Another participant points out a typo in the equation and suggests that writing the full equation may not always be necessary, proposing a method to include counterions for electrical neutrality.
  • A participant questions the balancing of the provided equation and asks for half-reactions to be worked out.
  • Another participant asserts that the equation is balanced but acknowledges the typo and requests clarification on what is perceived to be unbalanced.
  • A later reply confirms the equation is balanced once the typo is corrected, but does not provide further input.

Areas of Agreement / Disagreement

Participants express differing views on the balancing of the equation and the necessity of writing the full molecular equation. There is no consensus on the correct approach to writing the full equation or on the balancing status of the initial equation.

Contextual Notes

Some assumptions about the definitions of the species involved and the conditions under which the reaction occurs may be implicit in the discussion. The presence of a typo in the equation adds to the complexity of the balancing discussion.

new hand
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I want to ask what is the full equation of acidified potassium permanganate and potassium iodide?

I have worked out the ionic equation...

2 MnO4- + 16 H+ + 10I- --> 2Mn2+ + 8H2O + 5I2-

How to write the full equation??

THanks
 
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There is a typo - "-" at the end of the reaction equation (but otherwise it is OK).

new hand said:
How to write the full equation??

I don't think it is always possible (and actually rarely matters). In general - add counterions on the left side to make the solution electrically neutral (so start with KMnO4, HCl and KI), copy counterions on the right, try to pair them with anions on the right.
 
Your equation isn't balanced.
Can you work out its half-reactions?
 
war485 said:
Your equation isn't balanced.

It is balanced, it just contains a typo.

If it is not balanced - please tell us what is wrong.
 
ah yes sorry, it is balanced when the - on I2 is removed. I have nothing more to add.
 

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