X1, X2, X3 on a spnning fair wheel three times

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The discussion focuses on calculating the probability that three independent random variables, X1, X2, and X3, generated from a uniformly distributed fair wheel on the interval [0,1], are not within ±d of each other. Participants seek clarification on the joint distribution function fY2Y3(y2,y3) and the marginal distribution fX(y). The probability expression Pr[d≤Y2<=(1.2d), (Y2+d)≤Y3<=(1-d)] is also analyzed, emphasizing the need for understanding order statistics in this context.

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Three random variables are generated X1, X2, X3 on a spnning fair wheel three times. these variables are independent and uniformaly distributes on [0,1]. find probability that these values are none within +-d of each other where 0<=Y1<=Y2<=Y3<=1 is order statistics for randon variables.
fY2Y3(y2,y3) = 2!fx(y) . fX(y) =

what is fX(y)? can some one help?

Also,

Pr[d<=Y2<=(1.2d), (y2+d)<=Y3<=(1-d)] =

where y2 and y3 be placed in [0, 1]

I can understand it but don't know how to do it...
 
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