Y=-3sin(2x) shifted new equation?

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Homework Help Overview

The discussion revolves around the transformation of the sine function, specifically the equation y = -3sin(2x), and how it is affected by shifts in the horizontal and vertical directions. Participants are examining the correctness of a proposed new equation after applying a leftward shift of 30 degrees and an upward shift of 5 units.

Discussion Character

  • Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants are analyzing the transformation rules for sine functions, particularly how shifts are represented in the equation. There is a debate about whether the proposed equation correctly reflects a leftward shift and the implications of the signs in the transformation formula.

Discussion Status

There is an ongoing discussion with differing opinions on the correctness of the transformation. Some participants assert that the original poster's equation is incorrect, while others attempt to clarify the rules regarding shifts and the signs involved. No consensus has been reached, but multiple interpretations are being explored.

Contextual Notes

Participants are working within the constraints of the transformation rules for sine functions and are questioning the application of these rules to the specific shifts described. There is a focus on the implications of negative values in the context of horizontal shifts.

aisha
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y=-3sin(2x) is shifted to the left by 30 degree units and up 5 units

My new equation looks like this I am not sure if I did it right

y=-3sin[2(x-30)]+5

what do you think?
 
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Youre function is shifted to the right.

y=Asin(k(x-c)+b is shifted up b units, scaled vertically by A units, scaled horizontally by k units, and shifted to the right by c units. If c is negative then it is shifted to the left.
 
i want c to be negative because it says shift 30 degrees to the left, isn't this correct?
 
It is coerect and c must be negative but the formula itself has anothere - sing so they bouth together make a + and the expresion is then y=-3sin[2(x-(-30))]+5=-3sin[2(x+30))]+5
 
aisha said:
i want c to be negative because it says shift 30 degrees to the left, isn't this correct?
sorry, aisha, but your formula "y=-3sin[2(x-30)]+5" isn't correct.

I just entered "y = -3sin(2x)" and the other one in graphmatica and "y=-3sin[2(x-30)]+5" is definitely shifted to the right!

Edit: it shoulf be "y=-3sin[2(x+30)]+5"
 

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