Y coordinate of a charged particle

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SUMMARY

The discussion centers on calculating the y coordinate of a charged particle with a charge of 0.000003 C and mass of 0.000007 kg moving through an electric field of 6760 V/m. The equation used is y=(e*Em*x^2)/(2*m*v^2), where the participant initially used x in centimeters instead of meters, leading to incorrect results. After correcting the units and recalculating, the participant found an answer of 0.788 m, which was still marked incorrect, prompting a discussion about significant figures. The final conclusion suggests that the answer should be reported as 80 cm due to significant figure constraints.

PREREQUISITES
  • Understanding of electric fields, specifically 6760 V/m
  • Familiarity with the equation y=(e*Em*x^2)/(2*m*v^2)
  • Knowledge of unit conversions, particularly between centimeters and meters
  • Basic principles of significant figures in scientific calculations
NEXT STEPS
  • Review unit conversion methods for physics calculations
  • Study the concept of significant figures and their importance in scientific reporting
  • Explore the effects of electric fields on charged particles in more complex scenarios
  • Learn about common pitfalls in online homework systems and how to address them
USEFUL FOR

Students in physics, particularly those studying electromagnetism, as well as educators and anyone involved in online science education platforms.

Matt21
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Homework Statement


On the diagram, a charged particle of charge 0.000003 C and mass 0.000007 kg moves across the
electric field 6760 V/m with initial speed 40 m/s. When its x coordinate is 93.3 cm, its y coordinate is (in cm)?

Homework Equations


y=(e*Em*x^2)/(2*m*v^2), where Em is electric field, m is mass and v is speed.

The Attempt at a Solution


Using the equation given, I plugged in all the variables y=(0.000003*6760*93.3)/(2*0.000007*40^2) which gave me 7881 which is not correct. What am I doing wrong? Should I be plugging the charge of an electron (1.60*10^-19)? I'm almost positive this is the equation I need to use to figure it out. Any help would be much appreciated.
 

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Matt21 said:
y=(0.000003*6760*93.3)/(2*0.000007*40^2)
Your units do not match. ##E## is in V/m and ##v_{0}## is in m/s but your distance ##x## is in cm.
 
NFuller said:
Your units do not match. ##E## is in V/m and ##v_{0}## is in m/s but your distance ##x## is in cm.
Do I need to use distance x in m and then convert my answer for y back to cm? Because I've already done that and it still gives me the wrong answer. y=(0.000003*6760*0.933)/(2*0.000007*40^2)
 
Last edited:
Matt21 said:
Do I need to use distance x in m and then convert my answer for y back to cm?
Yes, what was your answer when you did this?
 
The answer I got was 0.788m which is 78.8cm. It says this is incorrect which doesn't make sense.
 
This is the correct answer. Is this a computer generated answer or is it written in your textbook?
 
It is an online prelab question I need to answer. Maybe it has to do with significant figures?
 
Matt21 said:
It is an online prelab question I need to answer.
Make sure there isn't some strange formatting issue which is causing the computer to reject your answer, such as having the units being entered a certain way. If you are sure this isn't the case then you should bring this to the attention of your professor. Its not uncommon for these programs to occasionally be programmed with a wrong answer.
 
Okay sounds good. Thank you very much for your help.
 
  • #10
Matt21 said:
Maybe it has to do with significant figures?
Good point actually. The lowest number of sig figs in the numbers they gave you is one. If the program is checking sig figs then your answer should be 80cm.
 

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