Relativistic charged particle in a constant, uniform EM field

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Homework Help Overview

The discussion revolves around finding the four-momentum \( p^\mu(\tau) \) of a relativistic charged particle in a constant, uniform electromagnetic field, specifically with an electric field \( E \) parallel to the y-axis and a magnetic field \( B \) parallel to the z-axis, where \( E = B \). The original poster has formulated differential equations based on these conditions but is uncertain about how to proceed with solving for the x and y components of the four-momentum.

Discussion Character

  • Exploratory, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants discuss the formulation of the equations of motion using the Lorentz force law and the structure of the electromagnetic field tensor. There are attempts to manipulate these equations to isolate components of the four-momentum. Some participants express uncertainty about the correctness of the derived equations and seek validation of their approaches.

Discussion Status

There is an ongoing exploration of the mathematical relationships between the components of the equations. Some participants have pointed out potential errors in the formulation of the electromagnetic field tensor and its implications for solving the equations. The discussion remains open, with various interpretations and methods being considered.

Contextual Notes

Participants note the assumption that \( E = B \) and the implications this has on the equations being solved. There is also mention of the original poster's reliance on methods found online, which raises questions about the originality of the approach being discussed.

Giuops
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Homework Statement
Find the four-momentum of a charged particle in an external, constant electric and magnetic field.
Relevant Equations
dpμ/dτ=q*Fμν*uν
pμ=muμ
I have to find pμ(τ) of a particle of mass m and charge q with v(0) = (vx(0), vy(0), vz(0)) in a electric field E parallel to the y-axis and a magnetic field B parallel to z axis, both constant and uniform, with E = B.

Here follows what I have done (see pictures below):

I wrote 4 differential equations (using that E=B) and called qE/m = a. The last equation (z axis) is immediately solved.

246552


To solve the others, I substituted equation (1) in (2) and (3), obtaining this:

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... but I don't know how to solve these. How do I find the x and y components of the four momentum?

Thanks for the read.
 
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ful disclosure i have seen this method online and not something i came up with myself

##
\frac{d P^{\mu}}{d \tau} = q F^{\mu \beta}u_{\beta}\\
##
i think ##F^{\mu \beta}## looks like this
##
\begin{pmatrix}
0&0&E&0\\
0&0&B&0\\
-E&-B&0&0\\
0&0&0&0
\end{pmatrix}
##
##
m\frac{d^2 u^{\mu}}{d \tau^2} = q F^{\mu \beta} \frac{d u_{\beta}}{d \tau}\\
m\frac{d^2 u^{\mu}}{d \tau^2} = \frac{q}{m} F^{\mu \beta} \frac{d P_{\beta}}{d \tau}\\
m\frac{d^2 u^{\mu}}{d \tau^2} = \frac{q^2}{m} F^{\mu \beta} F_{\beta \alpha}u^{\alpha}\\
F^{\mu \beta} F_{\beta \alpha} =
\begin{pmatrix}
E^2&-EB&E&0\\
-EB&-B^2&B&0\\
0&0&E^2-B^2&0\\
0&0&0&0
\end{pmatrix}
##
this has uncoupled the ##u^y## equation and since##E^2 - B^2 = 0## it is quite easy to solve for it and then you plug ##u^y## into earlier equations to get other components
someone tell me if it is wrong
 
timetraveller123 said:
##
F^{\mu \beta} F_{\beta \alpha} =
\begin{pmatrix}
E^2&-EB&E&0\\
-EB&-B^2&B&0\\
0&0&E^2-B^2&0\\
0&0&0&0
\end{pmatrix}
##
Looks like there are some "typos" here. We can let @Giuops find them if he/she wants to. :oldsmile:

This way of uncoupling the equations is pretty nifty.
 
Last edited:
TSny said:
Looks like there are some "typos" here.
oh i think i see them i think forgot to change some values after copying the first matrix
 

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