Yes, that is a valid example."Illustrating A in B and B in C not Implies A in C

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The discussion clarifies that the relationship A in B and B in C does not imply A in C through a specific example. In this case, A is defined as {1}, B as {2, {1}}, and C as {5, {2, {1}}}. The example demonstrates that while A is an element of B and B is an element of C, A is not an element of C. Participants acknowledge the validity of the example and suggest exploring additional rules or examples to illustrate the concept further. The conversation emphasizes the importance of understanding these relationships in set theory.
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Give an example to show that A\in B and B \in C does not imply that A \in C

Maybe I am misunderstanding the problem, but it seems as though there may be an infinite amount of solutions. For example: A = {1}, B = {2, {1}}, C = {5, {2, {1}}}

Is that correct?
 
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Yes, they only wanted AN example.

You could try giving two of `em, or maybe a "rule".
How many different KINDS of rules can you come up with?
 


Yes, that is a valid example. In this case, A = {1} is an element of B = {2, {1}}, and B is an element of C = {5, {2, {1}}}, but A is not an element of C. This shows that A \in B and B \in C does not necessarily imply that A \in C.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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