Yet another statics problem involving several forces

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SUMMARY

The discussion revolves around a statics problem involving a body connected to the ground with a movable joint at point B and sliding without friction at point A. Key equations used include ΣF=0 for force balance and ΣM=0 for moment balance. The user attempts to calculate forces and moments but encounters confusion regarding the distances involved in the moment calculations. The consensus is that the lack of friction at point A allows for sliding, but the specifics of the problem statement regarding forces P and M are unclear.

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  • Understanding of static equilibrium principles (ΣF=0 and ΣM=0)
  • Knowledge of force and moment calculations in statics
  • Familiarity with free body diagrams and their construction
  • Basic concepts of frictionless motion in mechanics
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  • Review the principles of static equilibrium in mechanics
  • Study how to construct and analyze free body diagrams
  • Learn about the effects of friction on motion and force distribution
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Students studying mechanics, particularly those focusing on statics, as well as educators looking for examples of force and moment calculations in frictionless systems.

mechanim
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Homework Statement


The body is connected to the ground with a moving joint at B, the body slides with no friction at A.
image.jpg


Homework Equations


ΣF=0 => ΣFx=0 & ΣFy=0
ΣM=0

The Attempt at a Solution


First I made a drawing:
222.png


At this point I started calculating:
ΣFx=>P-R2-F1, so: P=R2+F1
ΣFy=> R1+F2-mg=0, so: R1+F2=mg

I'm quite confused when it comes to the moment around B, I know that Moment=force*distance, but how do I draw all the distance that I need?

I thought about something like that:
222.png

So, the distance between F1 and the point B is a, while the distance between F2 and B is b.
Knowing this, I assume that the moment would look like that:

Mb: P+mg-F2*b-F1*a-R2-R1=0
now I replace P and mg according to the previous equations:
Mb: R2+F1+R1+F2-F2*b-F1*a-R2-R1=0
now the weird part is that I could reduce almost everything in the equation above, so that I would only be left with:
Mb: b-a=0
but it doesn't make any sense.

I would appreciate any help, thank you in advance!
 
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Two things:
1) the 'mg' force always acts from the center of mass of the object
2) how exactly does the body slide? Seems to be some mistake there
 
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2) how exactly does the body slide? Seems to be some mistake there

I don't think they are saying it slides. I think the point is that there is no friction at "a" so that it could slide if "b" wasn't there. If there was friction at "a" (or if "a" was another mounting like that at "b") then I think you would find it hard to calculate how forces are shared between "a" and "b".
 
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It says exactly that the body slides at A with no friction. I don't know exactly what they mean by that either. What do you think about the equations though?
 
What
mechanim said:
It says exactly that the body slides at A with no friction. I don't know exactly what they mean by that either. What do you think about the equations though?
what does it say about P and M?? In fact, what is the question as exactly worded?
 
That is the problem, it doesn't say anything about either P or M. I assume that M is supposed to be Moment, while P is a force, but the whole question is "The body in the picture is connected to the ground with a movable joint and slides without friction at A. Simplify the drawing and find the forces". It doesn't even say how far in the calculations I'm supposed to go.
 

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