The discussion centers on calculating the wavelength of visible light that results in a minimum at a specific location in a double-slit experiment, given that blue light with a wavelength of 460 nm produces a second-order maximum. The relevant equations for maxima and minima are provided: for maxima, sin A = m(wavelength)/d, and for minima, sin A = (m + 0.5)(wavelength)/d. By equating the two equations and substituting m1 = 2 and wavelength1 = 460 nm, participants determined that using m2 = 1 yields a wavelength of approximately 600 nm, which falls within the visible light spectrum.
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21385 said:The equation for double slit experiments when it is a maximum is
sin A=m(wavelength)/d. The equation for minimums is
sin A=(m+0.5)(wavelength)/d. Where A is the angle from where the observer will look at the spot on the screen. M is the "order" of the spots, whether it be max or min. d is the distance between the slits. Put all the constants on one side, which will be the sin A and d. Simple math and equating the equations together will get you the correct answer.
The question is a bit of vague, since it does not say what order is the minimum.
But it does say visible light.21385 said:The question is a bit of vague, since it does not say what order is the minimum.
21385 said:lol, i missed that ;)