Young'a double slit experiment

[kokok]

Homework Statement

in a double-slit experiment, blue light of wavelength 4.60*10^2 nm gives a second order maximum or CI at a certain location P on the screen. what wavelength of visible light would have a minimum or DI at P?

Homework Equations

x=(l*lamda)/separation

The Attempt at a Solution

I dun get it at all

 

[21385]

The equation for double slit experiments when it is a maximum is
sin A=m(wavelength)/d. The equation for minimums is
sin A=(m+0.5)(wavelength)/d. Where A is the angle from where the observer will look at the spot on the screen. M is the "order" of the spots, whether it be max or min. d is the distance between the slits. Put all the constants on one side, which will be the sin A and d. Simple math and equating the equations together will get you the correct answer.

The question is a bit of vague, since it does not say what order is the minimum.

 

[kokok]

The equation for double slit experiments when it is a maximum is
sin A=m(wavelength)/d. The equation for minimums is
sin A=(m+0.5)(wavelength)/d. Where A is the angle from where the observer will look at the spot on the screen. M is the "order" of the spots, whether it be max or min. d is the distance between the slits. Put all the constants on one side, which will be the sin A and d. Simple math and equating the equations together will get you the correct answer.

The question is a bit of vague, since it does not say what order is the minimum.

i don't know it was nelson's textbook chapter 9 review Qs

 

[Doc Al]

The question is a bit of vague, since it does not say what order is the minimum.

But it does say visible light.

 

[21385]

lol, i missed that ;)

 

[kokok]

lol, i missed that ;)

um..how should i start it...

 

[kokok]

How should i start it!?><

 

[21385]

well, just follow the instructions in my previous post

move the constants to one side for both equations and equate the other sides together.

m1(wavelength1)=(m2+0.5)(wavelength2)
you know that m1 is 2 and wavelength1 is 4.60*10^2 nm.
Now try different values for m2 that will result in a wavelength that's between 400 to 700 nm. (visible light)

 

[kokok]

oh, so when i replaced m2 to 1, i got about 600nm..i think thatz the answer.