The discussion revolves around a double-slit experiment involving blue light with a specific wavelength and the challenge of determining the wavelength of visible light that would produce a minimum at the same location on the screen. The subject area is optics, specifically interference patterns created by light passing through slits.
The discussion is active, with participants exploring different interpretations of the problem. Some guidance has been offered regarding the mathematical approach to equate the conditions for maxima and minima. There is acknowledgment of the ambiguity in the problem statement regarding the order of the minimum.
Participants note that the problem does not specify the order of the minimum, which may affect the solution. Additionally, there is a focus on the requirement for the resulting wavelength to fall within the visible spectrum.
21385 said:The equation for double slit experiments when it is a maximum is
sin A=m(wavelength)/d. The equation for minimums is
sin A=(m+0.5)(wavelength)/d. Where A is the angle from where the observer will look at the spot on the screen. M is the "order" of the spots, whether it be max or min. d is the distance between the slits. Put all the constants on one side, which will be the sin A and d. Simple math and equating the equations together will get you the correct answer.
The question is a bit of vague, since it does not say what order is the minimum.
But it does say visible light.21385 said:The question is a bit of vague, since it does not say what order is the minimum.
21385 said:lol, i missed that ;)