I Young's Double Slit Experiment: Is it Possible?

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The discussion centers on the challenges of applying Hamiltonian mechanics to Young's Double Slit Experiment due to the constraints on particle movement through the slits. There is a question about the feasibility of using constrained Hamiltonians in this context, suggesting that H could equal zero under certain conditions. Participants also explore the applicability of Feynman paths when the paths are restricted to a specific surface, such as a four-sphere. The complexities of these theoretical frameworks raise important questions about particle behavior in constrained environments. Overall, the conversation highlights the intricate relationship between quantum mechanics and mathematical formulations in physics.
Heidi
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I think that it is harder to describe the two slits Young experiment in terms of hamiltonian because the particle has a constraint: to pass through the slits. is it possible?
thanks.
 
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I think that it is harder to describe the two slits Young experiment in terms of hamiltonian because the particle has a constraint: to pass through the slits. is it possible? thanks.
 
How do you describe it without Hamiltonian?
 
my question is about the constrained hamiltonian if it is used. i do not says it does not exist. we may have H=0 with constrained hamiltonians so problems raise.
more generally can we use the feynman paths when the paths are constrained to live on a given surface (say a 4 sphere)
 
For the quantum state ##|l,m\rangle= |2,0\rangle## the z-component of angular momentum is zero and ##|L^2|=6 \hbar^2##. According to uncertainty it is impossible to determine the values of ##L_x, L_y, L_z## simultaneously. However, we know that ##L_x## and ## L_y##, like ##L_z##, get the values ##(-2,-1,0,1,2) \hbar##. In other words, for the state ##|2,0\rangle## we have ##\vec{L}=(L_x, L_y,0)## with ##L_x## and ## L_y## one of the values ##(-2,-1,0,1,2) \hbar##. But none of these...

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