Young's Slit Interference (Double Slit)

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SUMMARY

The discussion focuses on calculating the slit separation (a) in a double slit interference setup, where the interference fringes are 11.5 mrad apart using light of wavelength 471.0 nm. The relevant equations include tan(theta) = y/D and a*sin(theta) = p * wavelength. The user is advised to convert units appropriately and to consider the maxima and minima of the interference pattern for accurate calculations. Specifically, calculations for p = 1 and p = 2 are suggested to determine the angle differences between minima.

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singinglupine
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Find the slit separation of a double slit arrangement that will produce interference fringes 11.5 mrad apart on a distant screen with light of wavelength 471.0 nm.

tan(theta) = y/D
asin(theta) = p * wavelength

I know that I'm trying to solve for a, and that asin(theta) = 11.5, but I feel like I don't know enough information to solve the problem. Could someone point me in the right direction?
 
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The angle is θ = 11.5 mrad, the wavelength 471 nm so your expression should be more like
a*sin(11.5 mrad) = p*471 nm.
Be sure to get rid of the milli and the nano.

There is a little problem with that formula - it gives the angles for the minima whereas there is a maximum at θ = 0, so you'll have to do a couple of calculations perhaps for p = 1 and p = 2 to get a difference in angle between two minima.
 
Ah thanks. :)
 

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