Zero-force member problem (Statics)

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SUMMARY

The discussion focuses on identifying zero-force members in a truss structure using established rules of statics. The key rules applied include: if only two members meet at an unloaded joint, both are zero-force members; if three members meet at an unloaded joint with two in a direct line, the third is a zero-force member; and if two members meet at a loaded joint with the load's line of action coinciding with one member, the other is a zero-force member. The user initially identified six zero-force members (HF, HI, OQ, QR, BC, DE) but was confused about additional members (BE and IJ) noted in the solution. Clarification was provided that since BC is a zero-force member, it can be ignored, allowing the application of Rule #2 to identify BE and IJ as zero-force members.

PREREQUISITES
  • Understanding of truss structures and their components
  • Familiarity with statics principles and zero-force member rules
  • Basic knowledge of joint loading conditions in structural analysis
  • Ability to analyze truss diagrams and apply rules systematically
NEXT STEPS
  • Study the principles of truss analysis in engineering mechanics
  • Learn about different types of loads and their effects on truss members
  • Explore advanced topics in structural analysis, such as method of joints and method of sections
  • Practice identifying zero-force members in various truss configurations
USEFUL FOR

Students of civil and mechanical engineering, structural analysts, and anyone involved in truss design and analysis will benefit from this discussion.

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Homework Statement


Determine the zero force members in the following truss


Homework Equations



- If only two members meet in an unloaded joint, both are zero-force members.
- If three members meet in an unloaded joint of which two are in a direct line with one another, then the third member is a zero-force member.

- If two members meet in a loaded joint and the line of action of the load coincides with one of the members, the other member is a zero-force member.




The Attempt at a Solution



Ok, I got 6 (there are 8 according to the solution) using the above rules:
HF, HI, OQ, QR, BC, and DE

The solution says that BE and LJ are also zero force members, but I have no clue why...

Any help please?

Thanks in advance!
 

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Not LJ, its IJ, why? If BC is a zero force member, that should tell you something about BE (and DE).
 
Ok, I had thought about IJ before but since the solution didn't mention it I didn't count it...

Now, for BE: since BC is a zero-force member, can we "ignore" it and then consider the other 3 with Rule #2?
 
aero_zeppelin said:
Ok, I had thought about IJ before but since the solution didn't mention it I didn't count it...

Now, for BE: since BC is a zero-force member, can we "ignore" it and then consider the other 3 with Rule #2?
yes.
 
Thank you sir ;)
 

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