I regard a Klein-Gordon-field. But for the Klein-Gordon-Field, the commutation-relation is $$ [\Psi^\dagger (x,t), \partial_t \Psi (x',t)] = -i\hbar\delta(r-r')$$
I even know that: $$ [\Psi^\dagger(x,t), \Psi (x',t)] = 0$$
and $$ [\partial_t\Psi^\dagger(x,t), \partial_t \Psi (x',t)] = 0$$
and...