Yes, I'm still here.
Without getting into all the nitty-gritty with the inner workings of an LED driver/fixture, I believe I'm starting to understand a bit more how the loads after a point on a circuit affect the voltage drop.
Looking at this original question from an electrical install...
Yes, I believe 0.35 amp RMS sinewave. Just typical 120v AC 60 hz power you would find in the USA.
No PF control.
For simplicity, yes, just figure 120/.35=342.86 ohms.
This is actually a real world install. The .35A loads are LED bollard lights installed along a walkway. The #12 is THHN insulated wire installed 24" underground in PVC conduit. (I believe we actually installed #10 THHN) The 120v is AC nominal voltage,(could be anywhere from 115-125v, let's...
Sounds good, thank you for your time.
Mike Holt Voltage Drop This is a copy/paste from one source on that method. The chaper and tables are referencing the National Electric Code book.
Voltage Drop Using the Formula Method
When the circuit conductors have already been installed, the voltage...
I think we're getting off track. I know there are different methods of figuring voltage drop. You are using the resistivity of the copper wire. I'm using the 2KIL/CM method. That's a topic for another conversation. I guess I really just wanted to understand the science of how the voltage drop...
I'm trying to determine how to measure mathematically the voltage drop at various points along a circuit with loads at different points along the way. Let's assume all loads on 100% when the circuit is on. For a basic formula I use (for single phase): 2 * K-Value (12.9 Cu) * Amps *...