Recent content by Alec11

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    Establish Taylor series using Taylor's Theorem in terms of h

    It is possible if you're using Taylor's Theorem in terms of h that I specified in the OP.
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    Establish Taylor series using Taylor's Theorem in terms of h

    No, I gave you all of the information that is given. I assume they just want me to write out the first few terms of the series without evaluating it.
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    Establish Taylor series using Taylor's Theorem in terms of h

    Homework Statement Find the Taylor series for: ln[(x - h2) / (x + h2)] Homework Equations f(x+h) =∑nk=0 f(k)(x) * hk / k! + En + 1 where En + 1 = f(n + 1)(ξ) * hn + 1 / (n + 1)! The Attempt at a Solution ln[(x - h2) / (x + h2)] = ln(x-h2) - ln(x + h2) This is as far as I have been able to...
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    Potential difference due to a continuous charge distribution

    I get V = -6.20V, which actually turns out to be right. Looking back at my previous attempts, it seems I accidentally went from dq => rθdθ, instead of dq => rdθ, which explains why I thought I was wrong originally. Thanks for helping me figure that out!
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    Potential difference due to a continuous charge distribution

    I calculated λ=Q/(rθ) = (-25.6x10^(-12))/((2π/3)*(0.0371)) = (-3.29x10^(-10)) C/m It becomes (k/r)∫dq
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    Potential difference due to a continuous charge distribution

    Because I tried doing that for this homework problem and it results in a wrong answer. I looked up how to do it and someone said that you just reduce the equation to V=kq/r, which gives the correct answer. This held true for every homework problem with circular arc shaped charge distributions...
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    Potential difference due to a continuous charge distribution

    This is my first time using this site so please excuse me if I missed any guidelines. 1. Homework Statement A plastic rod having a uniformly distributed charge Q=-25.6pC has been bent into a circular arc of radius R=3.71cm and central angle ∅=120°. With V=0 at infinity, what is the electric...
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