Recent content by Ammar w

oh thank you gneill

Homework Statement Hi, We have this cut. : and in the image below, I10 is calculated by using current division : The Attempt at a Solution I tried to find it using voltage division but the answer is wrong : Vx(of the upper node) = 100 * \frac{j5}{4+j5} = 60.98 + j48.78 V => I10 =...

just give me the voltage of capacitor law. I don't know how to start,

Homework Statement what is the forced response for Rc cct. and how to derive it?? Homework Equations I know that the forced response in RL cct. is : i = cos (ωt - tan^-1 we start from : Vm cos (ωt) = Ri + L and i = I am cos (ωt-θ) Can anyone help please!

thanks and the KvL equation changes from : -120+V30+2VA-VA = 0 to : -120+V30-2VA+VA = 0

Homework Statement https://www.diigo.com/item/image/2sb3i/1svo Why don't we flip the signs of VA like this : https://www.diigo.com/item/image/2sb3i/g2a4 because the current must flow from + to - of the resistor. Homework Equations none The Attempt at a Solution none

aha thank you Mr. gneill

I'm sorry but can you tell me the equation of (a) if the potential change was "-8"? I thought that the equation +8-12+VR2 = 0 is used when the potential change = -8.

ok, how the solution of (a) will be if : https://www.diigo.com/item/image/2sb3i/y0us

thank you but I see that there is no difference if it was "+8" instead of "-8" ?

Homework Statement Click on the link https://www.diigo.com/item/image/2sb3i/yjim Homework Equations KVL Law Similar Example : https://www.diigo.com/item/image/2sb3i/orwa The Attempt at a Solution (a) In the left loop : -8-12+VR2 = 0 VR2 = -20 v (b) In the big loop ...

LastOneStanding, Thank you.

Homework Statement Here's the problem : http://www.diigo.com/item/image/2sb3i/wonu Homework Equations Ei = Ef The Attempt at a Solution The surface between A and B is frictionless : Ei = Ef KA + UA = KB + UB mghA = 1/2 mvB2 vB2 = 2ghA = 2*9.8*3 = 58.8 m/s The surface...

Homework Statement http://www.diigo.com/item/image/2sb3i/ahcq Homework Equations Ʃ\vec{F} = m\vec{a} The Attempt at a Solution For M : T - mg = ma T - 19.6 = 2a (1) For 2M : 40 cos (150) - T = 4a from (1) : T = 2a + 19.6 substituting : 40 cos (150) - (2a +19.6) = 4a 40 cos (150) - 19.6...

Homework Statement A projectile is fired from the top of a cliff of height h above the ocean below. The projectile is fired at an angle θ above the horizontal and with an initial speed vi. (a) Find a symbolic expression in terms of the variables vi, g, and θ for the time at which the projectile...