Recent content by AnthroMecha

I applied for one at Bell Hellicopter, it probably pays about half of what you're getting, LOL. I don't really care about that though, I just want a foot in the door.

Thanks for the response. I went ahead and applied for a summer 2013 internship.

I'm currently an ME student about half way through my Bachelor's degree and plan to graduate in 2 years. I'm older (37) and because of that I planned to get through my degree without doing an internship so I can get back to work asap. I don't mind taking a low paying job after I graduate for a...

This forum always delivers. Thanks guys these are very useful tools.

I am having the hardest time attaching my brain to some sort of method to know when to use sine and cosine on force problems. What is an easy way of remembering which function to use to find the force in the direction of x and force in the direction of y?

Yeah, I knew that answer sounded ridiculous.

Homework Statement A beam of electrons with energy 1.20 keV (per electron) is directed towards a solid copper sphere of radius 1.25cm. a) Determine the velocity of the electrons in the beam. b) The beam continues to send electrons into the sphere until it is charged up enough to repel the...

no. I'm wondering if it involves some sort of integral. I hope there's nothing like this one on the test, because I have to go take it in an hour, lol! I kind of procrastinated a bit on this one. :(

I'm coming up with 50964.4V electric potential (I may be using the wrong equation). I used V=(1/(4πε0))(q/r) q=4.83μC, r=85.2cm

Homework Statement A proton is moving with an initial velocity of 6.28x10^5 m/s straight towards a large conducting sphere of radius 85.2 cm. The sphere has a charge of 4.83 μC on it. Protons have a mass of 1.69x10^-27 kg. a) Determine how close the proton can come to the surface of the...

Oh, ok. Solving for the magnitude does simplify things.

Yeah, the minus sign came from me setting it up like this: 8.99 X 10^9 Nm^2/C^2 * (171μC*q2/15.1^2)+8.99 X 10^9 Nm^2/C^2 * (q2*q3/21.3^2)=0. I guess that q2 would be a negative charge, which I think would make the math correct. I'll have to keep an eye on that to make sure my answer is...

I stared at a while and realized I can cancel q2 and 8.99 X 10^9 Nm^2/C^2. I came up with q3= -340.25μC. I realized that the only way that the charges could balance out is if q3 is positive making the answer 340.25μC. Does this sound right?

Homework Statement Three charges are placed along a meter stick. One charge, q1, is placed at the 12.1cm mark. A second charge, q2, is placed at the 27.2cm mark. The third charge, q3, is placed at the 48.5cm mark. Charge q1 is equal to +171μC. What must be the sign and magnitude of charge q3...

You don't need it, but you'll be at an advantage over those that didn't take it. It was basically a run through of Cal I-Cal III basics in my class, and it helped me when it came to the harder aspects of Calculus to already have a basic understanding. Make sure you don't take your attention...