Recent content by artikk

According to the data sheet's first page, it's the rated DC load voltage. That particular switch can operate from 16.8 V to 61.2 V DC at the load.

What are the values for the DC power supplies you are using for the op amp? Because it could be the supplies are limiting your output voltage, depending on the output range of the supplies. If the supplies for your op amp are only capable of sourcing 4 V, you can't output higher than 4 V with...

There's a better way of proving it by using calculus, if you have the background. My professor in a circuit analysis course did this. Find the equation of power for the load resistor and then take it's derivative with respect to RL. Make Vg(source voltage) and Rth(source impedance) constants...

Hmm, I thought in rectangular waveguide problems, depending on type of boundary conditions used, the relevant tangential components to sides are 0. That might be why. For example, if a perfect magnetic conductor(pmc) boundary was employed at the left wall of the waveguide above, then Hy...

From what I remember in my antenna class, we've symbolically derived the pattern for array factor(I think), for specific size of an antenna array. Then, depending on the value of sidelobe value desired, appropriate filter coefficients were calculated to achieve the desired sidelobe values. These...

delta x and h are both variables to y, really, not x. The at^2 equation describes the displacement of the object in the vertical direction, not the the horizontal direction. If you you were to graph this equation it would show the distance traveled by the object in the y-direction. To find the...

In the course, yes. For electrical engineers, on the job at least, circuit simulation software such as SPICE is used instead to speed up the process.The software essentially uses systems of linear equations with some modifications to find the currents, voltages, etc.

I'm by no means a plasma expert but it seems to me that there wouldn't be different plasma types(at least classified by type of element/atom) since the electrons that are freed are the same for all elements.

http://en.wikipedia.org/wiki/Star

I think it would really have a gravitational field. Meaning any mass that comes in close contact with the planet, would experience gravitational attraction from the planet. However, a field is not a force. At this point, I think I better let a more eloquent physics poster explain how gravity...

Are you serious? That's impossible, I think. No mass can exert gravity on itself, just on other objects-it's fundamentally an attractive force. For a 3 kg mass, using just mechanics , any force that is exerted by this mass is exerted on the environment around the mass, not on the mass itself. A...

Doesn't that formula imply a second body though? Usually, the R and m would be that of the Earth, not the mass in question.

Like the other poster had said, you would need a second mass to calculate the gravitational force exerted by the first mass using Newton's gravitational force equation. In the case of general relativity as it concerns gravity, I don't think it requires a second mass. So, using general...

That symbol represents the heat flux across or through a plane, according to wiki. The symbol is a greek letter zeta.

The equation relates a NET force to the product of mass and acceleration. So even if you're pushing a wall, the applied force will probably will not be enough to move it since the wall is attached to the building and has its own weight. The force of the wall's weight and its connection with the...