Recent content by baywa2

Ok so Z parallel = [(XL∠90º)*R2] / [(XL∠90º)+R2] I get Z is some 37 Ω So do I then use R1 and C for Z? Z=R1+XC∠-90º Then add the Z and Zpar? 10+37+XC∠-90º -> 47+XC∠-90º

L=100mh=0.1H ω=10^3 rad/s -> f = 159Hz XL= ωL= 2πfL= 2π*159*0.1= 99.90 Ω Z parallel = [(XL∠90º)*R2] / [(XL∠90º)-R2]= 37.13∠-21.8º XC= 1/ωC= 1/(2 π f C) I don't see how I am supposed to get to C