Recent content by BenBa

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    Transmission Coefficient for Quantum Barrier

    Homework Statement Picture of Problem: Homework Equations $$\psi(x) = A_n e^{ikx} + B_n e^{-ikx}$$ for n=1,2,3 The Attempt at a Solution I know i need to relate the wave functions $$A_n e^{ikx} + B_n e^{-ikx}$$ for n=1,2,3 (the three areas of the barrier - before barrier, inside barrier...
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    Potential of two parallel infinite wires

    Homework Statement Two parallel infinite wires lay parallel to the z-axis in the xz-plane. One located at x=d has charge distribution λ and one located at x=-d has charge distribution -λ. Homework Equations a) Find the potential V(x,y,z) using the origin as a reference b)Show that...
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    Analysis of Cascode configuration Amplifier

    To study the clipping does that mean i need to draw the AC load lines for Q1 and Q2 and Q3 and see if the voltage hits saturation or the x axis? I feel like that's a really long way to find where clipping occurs. Also so the cascode configuation passes high frequencies from the high pass filter...
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    Analysis of Cascode configuration Amplifier

    R2 and R3 are in parallel to form an RC high pass filter with cutoff frequency 1/(2*pi*(R2||R3)*C2) = 6021.81 Hz. So any signals smaller than this will be chopped off, is this the f0 of the entire circuit though?
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    Diagramming an Active Filter: How Do I Calculate Ripple Control?

    Sorry i meant to say 20KHz, i was refferng to where you said: Can you explain this? I am trying to figure out why my diagram on the other forum is incorrect, i know the capacitor discharges slowly, but how does that effect the overall V of the ripple control?
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    Diagramming an Active Filter: How Do I Calculate Ripple Control?

    I'm sorry, can you explain what you mean about the "squashing" of the 20Hz signals and up due to the RC time constant? The capacitor charges up some and then slowly charges down but according to the ripple control formula the change in V is only equal to 0.02 volts, right? What is wrong with...
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    Diagramming an Active Filter: How Do I Calculate Ripple Control?

    Ihttp://forum.allaboutcircuits.com/showthread.php?p=675439#post675439, and i seem to have got a correct answer. But i may have made a mistake in my assumptions, do you see anything wrong with my logic? Also i think the bode plot is referring to the second stage that acts as a high pass active...
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    Analysis of Cascode configuration Amplifier

    Ah! That makes so much sense! because constant voltage sources are ground in AC analysis! Okay so if the voltage drops to ground over both R2 and R3 doesn't that mean that mean that that the currents through R2 and R3 are different? because the resistor values are different. I'm sorry but I...
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    Need help analyzing and audio amplifier [final exam study guide]

    I believe I have solved it after re-reading some sections in Horowitz and Hill. Thanks for all the help! Now i need just need to solve the cascode amplifier problem...
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    Analysis of Cascode configuration Amplifier

    Input is connected to capacitor, then to resistor, then to ground. In my circuit the input is at Vin, it passes the capacitor and then the current splits, some goes up to R2 and some into the base of Q1, and some down to R3. None of it goes to ground it seems, but i suppose that doesn't really...
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    Analysis of Cascode configuration Amplifier

    A capacitor and a resistor in series, with voltage out taken in between, right?
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    Analysis of Cascode configuration Amplifier

    Ah, i see now, sorry! I am just confused how to start with this question. I know you asked what kind of voltage divider C1, R2, and R3 create, but dividing between what two points?
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    Analysis of Cascode configuration Amplifier

    I looked up high pass RC network and it just gave me a simple RC passive filter. If C1 is a short to AC then the voltage divider at the node between C2, R2, and R3 is a low pass filter? How does that help us determine the frequency that causes distortion?
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    Need help analyzing and audio amplifier [final exam study guide]

    To check the gain across multiple frequencies can i use that the gain is (R2||C1)/R1? For high frequencies the R2||C1 just acts as a short, so that puts Vout at zero volts (because the positive terminal of the op amp is at zero). So does that make this a low pass filter?
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    Need help analyzing and audio amplifier [final exam study guide]

    Awesome! Thats great! So we are almost done! I just need feeback fraction and the open loop gain. I remember seeing somewhere that the feedback fraction was something like \frac{R_1}{R_1+/R_2} where R1 is the input resistor and R2 is the resistance of the feedback loop. Is this still correct if...
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