Recent content by Beowulf2007

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    Help: Proving the tending of an integral

    Hi Then limit must be \mathop{\lim} \limits_{t \to \infty} te^{-t^2} = 0, then assuming this is true then f(x1) an f(x2) then tend to the same limit since f is continious (by the mvt), and therefore the integral f(t) -> 0, then t tends to infinity? q.e.d. Cheers, Beowulf and thanks your...
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    Help: Proving the tending of an integral

    Homework Statement Given the integral f(t) = \int_{t}^{2t} e^{-x^2} dx How do I then prove that f(t) = 0 if t tends to infinity? Homework Equations The Attempt at a Solution I can that if I make t goes from minus infinity to zero, then the limit will tend to 1, but when...
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    Convergence of Cesáros Mean: Proving the Limit of a Sequence

    So the that for any epsilon, if n is arbitrary larger then Beta_n will stay small and will therefore tend to zero? And that is simply the proof? BR Beowulf
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    Simple Probability Question(HELP)

    Just so we understand each other. Do You mean? T \subseteq U and U \subseteq T Therefore their union is defined as T \cup U = T + U Therefore their intersection is defined as T \cap U = T \cdot U And then use this fact to claim that my result in (1) and (2) are true! How...
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    Simple Probability Question(HELP)

    Regarding (1) do I considered the events to the mutually exclusive?? And therefor if P(T) occurs then P(U) also occurs and thus P(T u U ) = P(T) + P(U)? Or is the explanation more simple?? In (2) Is it something to do with the events being mutually inclusive?? SR Beowolf
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    Convergence of Cesáros Mean: Proving the Limit of a Sequence

    Hi an Thank You for Your reply. I can see if I make n large then epsilon will have to be very small. Is the point that epsilon can only be larger than \alpha_n if n becomes extremely small? Sincerely Yours BeoWulf
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    Convergence of Cesáros Mean: Proving the Limit of a Sequence

    Convergens of Cesáros mean(Urgent). Homework Statement I need to show the following: (1) Let number sequence be given called \{\alpha_{n}\}_{n=1}^{\infty} for which \alpha_{n} \rightarrow 0 where n \rightarrow \infty. (2) Given a sequence \{\beta_{n}}\}_{n=1}^{\infty} which is...
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    Understanding Probability Functions

    Hello Hallsoft: Thank You for Your reply. I am sorry that the context of the problem was not clear. Here is the problem in its full context: Suppose we throw a red and white die simultaneously. The possible outcome of an experiment such as this can be recorded as follows: S =...
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    Simple Probability Question(HELP)

    Question(a) This will only work if P(TU) = 0? By this you mean proving that P(TU) = emptyset. The only that I know here is the that is the consequence of the formula P(T U U) = P(T) + P(U). Is that what you mean?? Question(b) Since nothing is said about the events being...
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    Understanding Probability Functions

    Homework Statement Given S = \{(r,w)| r,w = 1,2,\ldots, 6\} Deduce the following three probability functions. Probability that the number of eyes are red (1)P_{R}(t) = \frac{1}{6} for t \in \{1,2,\ldots 6 \} Probability that the number of eyes are either red or white...
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    Another Probability Question(Not so simple)

    Homework Statement An honest coin is throughn again and again until two consigutive heads or tails appears. Assume that the troughs are independent. Let T be the number of throughs which can take on the values 2,3,... Calculate P(T = n) for n = 2,3,... The Attempt at a Solution...
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    Simple Probability Question(HELP)

    Hello Again, The whole problem is as follows: Let (S, E, P) be a probability space and let T and U be events(Nothing is said about the events). Show, that if (1) P(T) = P(U) = 0 then P(T \cup U) = 0 (2) P(T) = P(U) = 1 then P(T \cap U) = 1 My Solultion(1):P(T \cup U) = P(T) +...
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    Simple Probability Question(HELP)

    From what I see it P(T \cap U) cannot be larger than one for obvious reasons. Because that would give a negative probability. I am not sure about that, another way of proving question (2) Could it say If P(C) is the entire probability space where then since P(T) = P(U), then I could say...
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    Simple Probability Question(HELP)

    Homework Statement Given that P(T) = P(U) = 0 then show that P(T \cup U) = 0 Given that P(T) = P(U) = 1 then show that P(T \cap U) = 1 Homework Equations I am told that I need to use the following equations. (1) P(T \cup U) = P(T) + P(U) if P(T \cap U) = 0 (2) P(T \cup U) =...
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