Recent content by billyray

thanks for help anyway Babadag

how do I work the G part out?

=4.294 x 10^-6 I mean sorry

Thanks Babadag so if I use Y2 = (0 + j.001349ꞷ )x length I can use 0 = G ꞷ=2xpix50Hertz and j0.001349/ꞷxlength =4.294 x 10^6 xlength for capacitance thanks again for helping

i have my capacitance as 4.294 x 10 to the power -6 does that seem correct?

I have looked at another post and they say: Shunt element = 1/C would my capacitance be 1/j.001349/w

I am a little confused about C as 0 + j.001349s = Y2 Y2 = (G + jωC) x length of line would g just be 0 and Capacitance be j.001349/2xpix50

ah ok I see thank you for the time and effort Babadag its most appreciated. R would then be 26.2565 and L j96.5901 / 2 x pi x 50 would Cs just be j 0.001349 /2x pi x 50 and G = 0

oh that means Z1 = 26.256 how would I go about getting Z1 = 0.5 (R +jωL)x line length ? would L be 0?

Hi Babadag Thanks for the help again. You mean they were wrong and mine is correct? so Z1 = 26.26 - j644.75

Homework Statement Figure shows a 50 Hz, high-voltage, transmission line. The relationships between the sending and receiving end voltages and currents are given by the complex ABCD equations: where 'S' stands for sending-end and 'R' stands for receiving-end (a) Given the parameter...

thanks gneil i will move on to the next one then.

hi thanks gneil. i have looked at this and my answer seems the same as i have used the same formula. on the first line of the equation they divide 0.5 by 2 and get 2.4. i know they are using a 10 to the power to mover decimal but 0.5 devided by 2 is 0.25 or am i missing something?

Homework Statement A transmission line has the primary coefficients . R=2Ω/m L=8nH/m G=0.5mS/m C=0.23pF/m Determine the lines secondary coefficients Z0, α and β at a frequency of 1GHz Homework Equations included in upload The Attempt at a Solution included. I think its just a case of...

Thanks so much Babadag I like your cat by the way.